<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Analytic Geometry |</title><link>https://sichen-wang.github.io/tags/analytic-geometry/</link><atom:link href="https://sichen-wang.github.io/tags/analytic-geometry/index.xml" rel="self" type="application/rss+xml"/><description>Analytic Geometry</description><generator>HugoBlox Kit (https://hugoblox.com)</generator><language>en-us</language><lastBuildDate>Mon, 13 Jan 2025 20:20:13 +0000</lastBuildDate><image><url>https://sichen-wang.github.io/media/icon_hu_9dfcb674aa885f38.png</url><title>Analytic Geometry</title><link>https://sichen-wang.github.io/tags/analytic-geometry/</link></image><item><title>三种曲线方程刻画方式的相互转换</title><link>https://sichen-wang.github.io/blog/%E4%B8%89%E7%A7%8D%E6%9B%B2%E7%BA%BF%E6%96%B9%E7%A8%8B%E5%88%BB%E7%94%BB%E6%96%B9%E5%BC%8F%E7%9A%84%E7%9B%B8%E4%BA%92%E8%BD%AC%E6%8D%A2/</link><pubDate>Mon, 13 Jan 2025 20:20:13 +0000</pubDate><guid>https://sichen-wang.github.io/blog/%E4%B8%89%E7%A7%8D%E6%9B%B2%E7%BA%BF%E6%96%B9%E7%A8%8B%E5%88%BB%E7%94%BB%E6%96%B9%E5%BC%8F%E7%9A%84%E7%9B%B8%E4%BA%92%E8%BD%AC%E6%8D%A2/</guid><description>&lt;p&gt;&lt;strong&gt;直角坐标方程&lt;/strong&gt;形如 \(y = f(x)\) 或 \(f(x, y) = 0\)，&lt;strong&gt;参数方程&lt;/strong&gt;形如
&lt;/p&gt;
\[
\begin{cases}
x = f(t) \\
y = g(t)
\end{cases}
\]&lt;p&gt;
&lt;strong&gt;极坐标方程&lt;/strong&gt;形如 \(\ell = \rho(\theta)\)。&lt;/p&gt;
&lt;h3 id="直角坐标方程转参数方程"&gt;直角坐标方程转参数方程&lt;/h3&gt;
\[
y = f(x) \Longrightarrow
\begin{cases}
x = t \\
y = f(t)
\end{cases}
\]&lt;h3 id="参数方程转直角坐标方程"&gt;参数方程转直角坐标方程&lt;/h3&gt;
&lt;ul&gt;
&lt;li&gt;代入法: 直接从 \(x = f(t)\) 解出 \(t = f^{-1}(x)\), 然后将其带入 \(y = g(t)\) 解得 \(x\) 和 \(y\) 关系.&lt;/li&gt;
&lt;li&gt;三角法: 如果方程涉及三角函数, 则可以利用三角恒等式解出直角坐标方程.
\[
\begin{cases}
x = r \cos t \\
y = r \sin t
\end{cases}
\Longrightarrow
x^2 + y^2 = r^2 (\sin^2 t + \cos^2 t) = r^2
\]&lt;/li&gt;
&lt;/ul&gt;
&lt;h3 id="极坐标方程转参数方程"&gt;极坐标方程转参数方程&lt;/h3&gt;
\[
\ell = \rho(\theta) \Longrightarrow
\begin{cases}
y = \rho(t) \sin t \\
x = \rho(t) \cos t
\end{cases}
\]&lt;h3 id="参数方程转极坐标方程"&gt;参数方程转极坐标方程&lt;/h3&gt;
&lt;p&gt;注意到在极坐标系中, 点的表示为
&lt;/p&gt;
\[
\begin{aligned}
\ell &amp;= \sqrt{x^2 + y^2} \\
\theta &amp;= \arctan \frac{y}{x}
\end{aligned}
\]&lt;p&gt;于是将参数方程带入即可得出 \(\ell, \theta\) 与 \(t\) 的关系, 设 \(\ell = p(t), \theta = \arctan q(t)\), 则
&lt;/p&gt;
\[
\ell = p \circ q^{-1}(\tan \theta)
\]</description></item></channel></rss>